Arduino: Serial. Print a Multiple-Character Element
I Need to Print 4-Bit Long Numbers, These Numbers Are Binary Numbers Frome 0 to 16 (0000, 0001, 0010, .. .). Problems: Considering This Code: Char Array[] =...
I need to print 4-bit long numbers, these numbers are Binary numbers frome 0 to 16 (0000, 0001, 0010, ...).
PROBLEMS:
Considering this code:
char array[] = {'0000', '0001', '0010', '0011'};
int i;
void setup() {
Serial.begin(9600);
}
void loop() {
while (i < 4){
Serial.println(array[i]);
i++;
}
}
The serial monitor outputs:
0
1
0
1
My expected output is:
0000
0001
0010
0011
It seems that only the first "character" of each element of the array is read.
QUESTION: How can I print the entirety of each element like in my expected output?
After some reasearch, I found this:
which then refers to using PROGMEM but I'm not sure if this is what I need or if there is a simpler solution to my problem.
1 Answer
As mentioned in the comments, don't use multi-character constants (the ones you used, with single quotes); they might kill puppies. Single quotes are for character constants, like 'a'.
You can use strings (with double quotes), or real binary numbers without trickery; the latter will print without leading zeros.
This code example does both, so pick what you need:
const char* array1[] = {"0000", "0001", "0010", "0011"}; // strings
uint8_t array2[] = {0b000, 0b0001, 0b0010, 0b0011}; // binary numbers
int arraySize = sizeof(array1) / sizeof(array1[0]);
void setup() {
Serial.begin(9600);
while (!Serial);
Serial.println("Print the strings:");
int i = 0;
while (i < arraySize){
Serial.println(array1[i]);
i++;
}
Serial.println("\nPrint the binary numbers (note: no leading zeroes):");
i = 0;
while (i < arraySize){
Serial.println(array2[i], BIN);
i++;
}
}
void loop() {
}
James Sterling reports on renewable energy developments, climate policy, ecological conservation, and green tech innovations around the globe.
