C to Assembly - Leaq Instruction [Duplicate]
As Far as I Understood: %Rdi = 1St Argument = X %Rsi = 2Nd Argument = Y %Rdx = 3Rd Argument = Z the Others Manipulate These Registers. .. and Store in a Return...
![C to Assembly - Leaq Instruction [Duplicate]](https://www.alledaags.nl/uploads/c-to-assembly-leaq-instruction-duplicate_1200.jpg)
As far as I understood:
- %rdi = 1st argument = x
- %rsi = 2nd argument = y
- %rdx = 3rd argument = z
- The others manipulate these registers... and store in a return value register
The 3rd line on the assembly code leaq (%rsi, %rsi, 2), %rdx, which as I translate it: z = y + 2*y.
I'm confused, is this code wrong, or is it an assembly magic?
simple explanation
it moves the address not the values
Sarah Jenkins is a veteran tech journalist with over 12 years of experience covering artificial intelligence, mobile innovations, and digital ethics. Her insights have appeared in leading technology publications worldwide.
