Can We Call Method Using a Variable If Variable Is None?
The Following Code, Which I Am Trying to Run and the Value of Var_Pg Is Showing 0. the Question Is That Why Is It Showing 0 Whereas the Fitness Function Is...
The following code, which I am trying to run and the value of var_pg is showing 0. The question is that why is it showing 0 whereas the fitness function is returning some value which is greater than 0?
def main():
pop = {0,1,2,4,3,5}
var_pg = find_best(pop)
print('value of var_pg',var_pg)
def find_best(pop):
var_pg = None
for p in pop:
if (not var_pg) or (var_pg.fitness()>p.fitness()):
var_pg=p
return var_pg
class CP:
def fitness(self):
c = 0.1*(5/41)
self.__fitness = c
return self.__fitness
main()
Can somebody please tell me what's am I doing wrong here?
2 Answers
At the first iteration of for p in pop, p is assigned to 0. not var_pg is thus True, so var_pg is assigned to 0 and returned, terminating the loop.
return var_pgshould likely go outside theforloop- The arguments passed in
popare just integers, notCPobjects, so they have nofitness()method.
Because return var_pg is inside the loop and unconditional, the find_best() function will always return the first elements it gets from pop. since pop is a set it could be any of the values. It just happens to be zero in this case.
Robert Thorne covers electric vehicle innovations, autonomous driving systems, global mobility trends, and automotive engineering developments.
