Checking If Any Character in a String Is Alphanumeric
I Want to Check If Any Character in a String Is Alphanumeric. I Wrote the Following Code for That and It's Working Fine: S = Input() Temp = Any(I. Isalnum()...
I want to check if any character in a string is alphanumeric. I wrote the following code for that and it's working fine:
s = input()
temp = any(i.isalnum() for i in s)
print(temp)
The question I have is the below code, how is it different from the above code:
for i in s:
if any(i.isalnum()):
print(True)
The for-loop iteration is still happening in the first code so why isn't it throwing an error? The second code throws:
Traceback (most recent call last): File "", line 18, in TypeError: 'bool' object is not iterable
2 Answers
In your second function you apply any to a single element and not to the whole list. Thus, you get a single bool element if character i is alphanumeric.
In the second case you cannot really use any as you work with single elements. Instead you could write:
for i in s:
if i.isalnum():
print(True)
break
Which will be more similar to your first case.
any() expects an iterable. This would be sufficient:
isalnum = False
for i in s:
if i.isalnum():
isalnum = True
break
print(isalnum)
Maya is a hardware enthusiast who tests and reviews smart home devices, smartphones, wearables, and audio gear. She focuses on practical consumer value and build quality.
