Creating a New Dictionary in Python

You can do this

x = {}
x['a'] = 1

Knowing how to write a preset dictionary is useful to know as well:

cmap =  {'US':'USA','GB':'Great Britain'}

# Explicitly:
# -----------
def cxlate(country):
    try:
        ret = cmap[country]
    except KeyError:
        ret = '?'
    return ret

present = 'US' # this one is in the dict
missing = 'RU' # this one is not

print cxlate(present) # == USA
print cxlate(missing) # == ?

# or, much more simply as suggested below:

print cmap.get(present,'?') # == USA
print cmap.get(missing,'?') # == ?

# with country codes, you might prefer to return the original on failure:

print cmap.get(present,present) # == USA
print cmap.get(missing,missing) # == RU

>>> dict(a=2,b=4)
{'a': 2, 'b': 4}

Will add the value in the python dictionary.

d = dict()

or

d = {}

or

import types
d = types.DictType.__new__(types.DictType, (), {})

So there 2 ways to create a dict :

1. my_dict = dict()

2. my_dict = {}

But out of these two options {} is more efficient than dict() plus its readable. CHECK HERE

>>> dict.fromkeys(['a','b','c'],[1,2,3])


{'a': [1, 2, 3], 'b': [1, 2, 3], 'c': [1, 2, 3]}

I do not have enough reputation yet to be able comment, so I share this as an answer.

The link shared by @David Wheaton in his comment to the accepted answer is no longer valid as Doug Hellmann has migrated his site (source: ).

Here is the updated link about "The Performance Impact of Using dict() Instead of {} in CPython 2.7":