Curl Error "Url Using Bad/Illegal Format or Missing Url" When Trying to Pass Variable as a Part of Url
When I'm Trying to Execute Script Below and Getting Error: "Curl: (3) Url Using Bad/Illegal Format or Missing Url" #! /Bin/Bash Stage="Develop"...
When I'm trying to execute script below and getting error: "curl: (3) URL using bad/illegal format or missing URL"
#!/bin/bash
stage="develop"
branch="branch_name"
getDefinition=$(curl -u :password -X GET "")
for def in $(echo "$getDefinition" | jq '.value[] | select (.path=="\\Some_path\\'$stage'") | .id'); do
getBuildInfo=$(curl -u :password -X GET "")
# echo $def
body=$(echo "${getBuildInfo}" | jq '.repository.defaultBranch = "refs/heads/release/'"${branch}"'"' | jq '.options[].inputs.branchFilters = "[\"+refs/heads/release/'"${branch}"'\"]"' | jq '.triggers[].branchFilters[] = "+refs/heads/release/'"${branch}"'"')
echo ${body} > data.json
done
It happens when I'm trying to pass variable ${def} into a line:
curl -u :password -X GET ""
But when I declare an array, curl works as expected. Example:
declare -a def
def=(1 2 3 4)
curl -u :password -X GET ""
Could you please suggest how can I pass variable into URL properly?
1 Answer
Do you need to call curl for 4 times? If so.
for def in 1 2 3 4; do curl -u :password -X GET ""; done