Dynamically Construct Variables Inside the Script and Fetch Values from Source Parameters
I Have a Txt File Extract. Dat Which Is Read Inside My Code Using Source. $ Cat Extract. Dat Exchgrate_Prop="Edb_Name=Share_Exchange Src_Wds=Wds Pn=Exchgrate"...
I have a txt file extract.dat which is read inside my code using source.
$ cat extract.dat
ExchgRate_prop="EDB_NAME=share_exchange SRC_WDS=wds PN=ExchgRate"
Compliance_prop="EDB_NAME=share_compliance SRC_WDS=wca PN=com"
Unitcost_prop=="EDB_NAME=share_unitcost SRC_WDS=wda PN=unit"
source ./ extract.dat
now I would have got all the varaibles inside my code. if my code takes an argument $PROJ with value as 'ExchgRate' , how can i concatenate "$PROJ""_prop" to create the variable ExchgRate_prop and then get value "EDB_NAME=share_exchange SRC_WDS=wds PN=ExchgRate"
1 Answer
You can use bash variable indirection. Ex. given
$ echo "$ExchgRate_prop"
EDB_NAME=share_exchange SRC_WDS=wds PN=ExchgRate
and
$ PROJ=ExchgRate
then
$ var=${PROJ}_prop
$ echo "${!var}"
EDB_NAME=share_exchange SRC_WDS=wds PN=ExchgRate
Alexander Ross has covered the video game industry for a decade, writing deep dives on game design, esports tournaments, VR developments, and gaming culture.
