For anyone in the future looking for an answer, I would like to give a much clearer answer to the question.

# for making a tuple
my_tuple = (89, 32)
my_tuple_with_more_values = (1, 2, 3, 4, 5, 6)

# to concatenate tuples
another_tuple = my_tuple + my_tuple_with_more_values
print(another_tuple)
# (89, 32, 1, 2, 3, 4, 5, 6)

# getting a value from a tuple is similar to a list
first_val = my_tuple[0]
second_val = my_tuple[1]

# if you have a function called my_tuple_fun that returns a tuple,
# you might want to do this
my_tuple_fun()[0]
my_tuple_fun()[1]

# or this
v1, v2 = my_tuple_fun()

Hope this clears things up further for those that need it.

General

Single elements of a tuple a can be accessed -in an indexed array-like fashion-

via a[0], a[1], ... depending on the number of elements in the tuple.

Example

If your tuple is a=(3,"a")

• a[0] yields 3,
• a[1] yields "a"

Concrete answer to question

def tup():
  return (3, "hello")

tup() returns a 2-tuple.

In order to "solve"

i = 5 + tup()  # I want to add just the three

you select the 3 by:

tup()[0]    # first element

so all together:

i = 5 + tup()[0]

Alternatives

Go with namedtuple that allows you to access tuple elements by name (and by index). Details are at

>>> import collections
>>> MyTuple=collections.namedtuple("MyTuple", "mynumber, mystring")
>>> m = MyTuple(3, "hello")
>>> m[0]
3
>>> m.mynumber
3
>>> m[1]
'hello'
>>> m.mystring
'hello'