How Can I Do 'A' + 1 #=> 'B' in Python?

define your own function:

In [103]: def func(c,n):
    return chr(ord(c)+n)
   .....: 

In [105]: func('a',-1)
Out[105]: '`'

In [106]: func('b',-1)
Out[106]: 'a'

In [107]: func('c',2)
Out[107]: 'e'

Python is strongly typed and considerer strings and ints are different, and won't convert one to another implicitly.

However, you code can probably be simplified to

chr(ord('b') + 1)

If you use it a lot, put it in a function, and don't worry about it any more :

def incr_char(c, n):
    return chr(ord(c) + n)

Try this instead:

>>> import string
>>> string.letters[string.letters.index('a')+1]
'b'

Just for Ashwini:

>>> string.letters[string.letters.index('a')-1]
'Z'

You can do something like:

class char(unicode):
    def __add__(self, x):
        return char(unichr(ord(self) + x))

print char('a') + 1 # b