How Do I Populate a List from a Repeating Section Content Control Form Field in Word 2016?

I am way out of my depth on this — I’ve never even heard of RSCCs before I saw your question — but I’ve cobbled together something that may be part of your solution.  I assume that your data are in a table, and that your “name” field is column 1.  Enter this VBA code:

Sub listControl_1()
    Dim o As Table
    Dim c As Row
    Dim mylist As Variant

    Set o = ActiveDocument.ContentControls.Item(1).Range.Tables(1)
    rownum = 0
    For Each c In o.Rows
        rownum = rownum + 1
        If rownum > 1 Then
            thislen = Len(c.Cells(1).Range.Text)
            If thislen > 0 Then
                thislen = thislen - 1
            End If
            If rownum = 2 Then
                mylist = Mid(c.Cells(1).Range.Text, 1, thislen)
            Else
                mylist = mylist & ", " & Mid(c.Cells(1).Range.Text, 1, thislen)
            End If
        End If
    Next c
    MsgBox mylist
End Sub

The If rownum > 1 Then test assumes that your table has a header row (and skips it, so you don’t get the header text in the list).  If you don’t have a header row (or if you have more than one), adjust the code accordingly.  Each cell seems to have a delimiter character at the end; the code uses Mid() to strip that off.

This assembles a comma-separated list of the values for column 1 of the first table, and displays it in a message box.  If your data are not in a table, I don’t know what to tell you.  If your data are in a table, but it’s not the first one in the document, I don’t know how to find the right one.  And, most importantly, I don’t know how to get the list into your document.  As I said, this is at best a part of your solution.

I copied the framework of the VBA code from MSDN’s “How to get a value from content control within Repeating section content control”.  (There’s more code there, which you might find useful.)  Note that their code does Mid(text, 1, Len(text) - 2).  I tried subtracting 2 from the length, and I lost the last character of the text; I don’t know why it’s different.  Also I notice that their code does c.Cells(columnNumber).Range.Text = someText to write data into the table.  Perhaps you can use this as a clue to figure out how to get the result from the routine into your document.