How Do I Write a Shell Script for Checking Website Live or Not
I Am Writing a Shell Script to Monitor Website Live or Not and Send an Email Alert Below Is My Code #! /Bin/Bash If [[ Curl -S --Head --Request Get | Grep "200...
I am writing a shell script to monitor website live or not and send an email alert below is my code
#!/bin/bash
if [[ curl -s --head --request GET | grep "200 OK" > /dev/null] && [ curl -s --head --request GET | grep "200 OK" > /dev/null ]]
then echo "The HTTP server on opx.com and oss.com is up!" #> /dev/null
else
msg="The HTTP server opx.com Or oss.com is down "
email=""
curl --data "body=$msg &to=$email &subject=$msg"
fi;
if i run this code i got
./Monitoring_Opx_Oss: line 2: conditional binary operator expected
./Monitoring_Opx_Oss: line 2: syntax error near `-s'
./Monitoring_Opx_Oss: line 2: `if [[ curl -s --head --request GET | grep "200 OK" > /dev/null] && [ curl -s --head --request GET | grep "200 OK" > /dev/null ]] '
Please correct me...
1 Answer
Change it do this:
if [ $(curl -s --head --request GET | grep "200 OK" > /dev/null) ] && [ $(curl -s --head --request GET | grep "200 OK" > /dev/null) ]
To check the status of a command inside an if, you have to do it like
if [ $(command) ]
while you were using
if [ command]
note also the need of spaces around [ ]: if [_space_ command _space_ ]
Update
Based on Ansgar Wiechers's comment, you can also use the following:
if curl -s --head --request GET | grep "200 OK" > /dev/null && curl -s --head --request GET | grep "200 OK" > /dev/null;
That is,
if command && command
Elena Rostova holds a Master's degree in Public Health Journalism. She covers groundbreaking medical research, holistic wellness trends, mental health awareness, and nutritional science.
