How to Convert a Propositional Formula to Conjunctive Normal Form (Cnf)?

How can I convert this equation to CNF?

¬((p ∨ ¬Q) ⊃ R) ⊃ (P ∧ R))
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4 Answers

To convert a propositional formula to conjunctive normal form, perform the following two steps:

  1. Push negations into the formula, repeatedly applying De Morgan's Law, until all negations only apply to atoms. You obtain a formula in negation normal form.

    • ¬(p ∨ q) to (¬p) ∧ (¬q)

    • ¬(p ∧ q) to (¬p) ∨ (¬q)

  2. Repeatedly apply the distributive law where a disjunction occurs over a conjunction. Once this is not possible anymore, the formula is in CNF.

    • p ∨ (q ∧ r) to (p ∨ q) ∧ (p ∨ r)

To obtain a formula in disjunctive normal form, simply apply the distribution of ∧ over ∨ in step 2.

Note about ⊂

The subset symbol (⊂) used in the question is just an alternative notation for the logical implication/entailment, which is usually written as an arrow (⇒).

To convert first-order logic to CNF:

  1. Convert to Negation normal form.
    1. Eliminate implications: convert x → y to ¬ x ∨ y
    2. Move NOTs inwards.
  2. Standardize variables
  3. Skolemize the statement
  4. Drop universal quantifiers
  5. Distribute ANDs over ORs.

(Artificial Intelligence: A modern Approach [1995...] Russel and Norvig)

1

Might I suggest this? There is an algorithm for conversion on the page.

Conjunctive Normal Form

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I have implemented a small tool in Java that can do basic transformation from a boolean expression into (C|D)NF. If you are interested, you might want to have a look at . The implementation is based on these lecture notes. A more detailed description can be found here. Any feedback would be greatly appreciated ;-).

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Maya Lin-Takahashi

Maya Lin-Takahashi

Consumer Tech & Gadget Reviewer

Maya is a hardware enthusiast who tests and reviews smart home devices, smartphones, wearables, and audio gear. She focuses on practical consumer value and build quality.

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