Use the type() builtin function:

>>> i = 123
>>> type(i)
<type 'int'>
>>> type(i) is int
True
>>> i = 123.456
>>> type(i)
<type 'float'>
>>> type(i) is float
True

To check if a variable is of a given type, use isinstance:

>>> i = 123
>>> isinstance(i, int)
True
>>> isinstance(i, (float, str, set, dict))
False

Note that Python doesn't have the same types as C/C++, which appears to be your question.

You may be looking for the type() built-in function.

See the examples below, but there's no "unsigned" type in Python just like Java.

Positive integer:

>>> v = 10
>>> type(v)
<type 'int'>

Large positive integer:

>>> v = 100000000000000
>>> type(v)
<type 'long'>

Negative integer:

>>> v = -10
>>> type(v)
<type 'int'>

Literal sequence of characters:

>>> v = 'hi'
>>> type(v)
<type 'str'>

Floating point integer:

>>> v = 3.14159
>>> type(v)
<type 'float'>

It is so simple. You do it like this.

print(type(variable_name))

How to determine the variable type in Python?

So if you have a variable, for example:

one = 1

You want to know its type?

There are right ways and wrong ways to do just about everything in Python. Here's the right way:

Use type

>>> type(one)
<type 'int'>

You can use the __name__ attribute to get the name of the object. (This is one of the few special attributes that you need to use the __dunder__ name to get to - there's not even a method for it in the inspect module.)

>>> type(one).__name__
'int'