How to Dynamically Build a Json Object?
I Am New to Python and I Am Playing with Json Data. I Would Like to Dynamically Build a Json Object by Adding Some Key-Value to an Existing Json Object. I...
I am new to Python and I am playing with JSON data. I would like to dynamically build a JSON object by adding some key-value to an existing JSON object.
I tried the following but I get TypeError: 'str' object does not support item assignment:
import json
json_data = json.dumps({})
json_data["key"] = "value"
print 'JSON: ', json_data
8 Answers
You build the object before encoding it to a JSON string:
import json
data = {}
data['key'] = 'value'
json_data = json.dumps(data)
JSON is a serialization format, textual data representing a structure. It is not, itself, that structure.
You can create the Python dictionary and serialize it to JSON in one line and it's not even ugly.
my_json_string = json.dumps({'key1': val1, 'key2': val2})
There is already a solution provided which allows building a dictionary, (or nested dictionary for more complex data), but if you wish to build an object, then perhaps try 'ObjDict'. This gives much more control over the json to be created, for example retaining order, and allows building as an object which may be a preferred representation of your concept.
pip install objdict first.
from objdict import ObjDict
data = ObjDict()
data.key = 'value'
json_data = data.dumps()
You can use EasyDict library (doc):
EasyDict allows to access dict values as attributes (works recursively). A Javascript-like properties dot notation for python dicts.
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