How to Prepare Salkowski Reagent?
Salkowski Reagent (Prepared for the Class): in the Fume Hood, Mix 2 Ml 0.5M Fecl3 and 49 Ml Water and 49 Ml 70% Perchloric Acid (Oxidizer! Corrosive!). 0.5M...
Salkowski Reagent (prepared for the class): In the fume hood, mix 2 ml 0.5M FeCl3 and 49 ml water and 49 ml 70% perchloric acid (Oxidizer! Corrosive!). 0.5M ferric chloride solution: the formula/molecular weight is 270.3 so you would need 270.3 g for a liter of 1 M solution. For 10 ml, you would need 2.7g for 1 M.
How do you make salkowski reagent?
Salkowski reagent consisted of a mixture of 15 ml 0.5 M FeCl3, 500 ml distilled water, and 300 ml of concentrated H,S04 sp.
What is Salkowski reagent?
Salkowski reagent is a mixture of 0.5 M ferric chloride (FeCl3 ) and 35% perchloric acid (HClO4) which upon reaction with IAA yields pink color, due to IAA complex formation with and reduction of Fe3+ ( Kamnev et al., 2001 ).
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