How to Print Unsigned Char[] as Hex in C++?
I Would Like to Print the Following Hashed Data. How Should I Do It? Unsigned Char hashedChars[32]; Sha256((Const Unsigned Char*)Data. C_Str(), Data. Length()...
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I would like to print the following hashed data. How should I do it?
unsigned char hashedChars[32];
SHA256((const unsigned char*)data.c_str(),
data.length(),
hashedChars);
printf("hashedChars: %X\n", hashedChars); // doesn't seem to work??
2 Answers
The hex format specifier is expecting a single integer value but you're providing instead an array of char. What you need to do is print out the char values individually as hex values.
printf("hashedChars: ");
for (int i = 0; i < 32; i++) {
printf("%x", hashedChars[i]);
}
printf("\n");
Since you are using C++ though you should consider using cout instead of printf (it's more idiomatic for C++.
cout << "hashedChars: ";
for (int i = 0; i < 32; i++) {
cout << hex << hashedChars[i];
}
cout << endl;
In C++
#include <iostream>
#include <iomanip>
unsigned char buf0[] = {4, 85, 250, 206};
for (int i = 0;i < sizeof buf0 / sizeof buf0[0]; i++) {
std::cout << std::setfill('0')
<< std::setw(2)
<< std::uppercase
<< std::hex << (0xFF & buf0[i]) << " ";
}
James Sterling reports on renewable energy developments, climate policy, ecological conservation, and green tech innovations around the globe.
