In a Parallel Plate Capacitor with Plate Area a?

A parallel plate capacitor of plate area A and plate separation d is charged to potential difference V and then the battery is disconnected. A slab of dielectric constant K is then inserted between the plates of capacitor so as to fill the space between the plates.

What is the area of a parallel plate capacitor?

To calculate the area of the plates of a one farad parallel plate capacitor, we have separation between plates is $1mm$ and ${\varepsilon _0} = 8.854 \times {10^{ - 12}}F{m^{ - 1}}$. As there is vacuum between two plates $k = 1$ .

What happens to the capacitance of a parallel plate capacitor if the area of plates is doubled and separation between the plates is halved?

What will happen if the area and separation of a parallel plate capacitor are doubled? If the area is doubled with the other parameters being constant, then the capacitance would double. If the distance of separation were doubled with the others constant, then the capacitance would be halved.