Is Adjoint Operator Linear?
[Edit] Existence of the Adjoint When T Is a Bounded Operator (Hence D(T) = H) Then It Can Be Shown, Again Using the Riesz Representation Theorem, That T∗ Is...
[edit] Existence of the adjoint
When T is a bounded operator (hence D(T) = H) then it can be shown, again using the Riesz representation theorem, that T∗ is the unique bounded linear operator satisfying equation (2).
How do you know if an operator is linear?
A function f is called a linear operator if it has the two properties:
- f(x+y)=f(x)+f(y) for all x and y;
- f(cx)=cf(x) for all x and all constants c.
How do you find the adjoint of a linear operator?
We have that 〈x,T(y)〉 = 〈T(y),x〉 = 〈y,T∗(x)〉 = 〈T∗(x),y〉. Let A = (aij ) be an m × n matrix with complex entries. The adjoint matrix of A is the n × m matrix A∗ = (bij ) such that bij = aji . That is, A∗ = At.