Javascript Function Returning Day of Week X Num of Days Later
What I Am Trying to Write Is a Simple Function That Takes in a Day (D), X Number of Days and Returns the Day X Days Later. Days Can Be Represented by ('Mon'...
What I am trying to write is a simple function that takes in a day (D), X number of days and returns the day X days later.
Days can be represented by ('Mon', 'Tue', 'Wed', 'Thu','Fri','Sat','Sun').
X can be any int 0 and up.
For Example D='Wed', X='2', return 'Fri', D='Sat' and X='5', returns 'Wed'.
How do I do this in JS? Any tips and suggestions appreciated.
1 Answer
If I understand your question correctly, then perhaps you could do something like the following:
- find the index of input "d" against days of the week
- apply "x" to offset the found index
- apply modulo operator by total number of days (7) to revolve offset index around valid day range
- return resulting day by that computed index
Here's a code snippet - hope that helps!
function getWeekDayFromOffset(d, x) {
// Array of week days
const days = ['Mon', 'Tue', 'Wed', 'Thu','Fri','Sat','Sun'];
// Find index of input day "d"
const dIndex = days.indexOf(d);
// Take add "x" offset to index of "d", and apply modulo % to
// revolve back through array
const xIndex = (dIndex + x) % days.length;
// Return the day for offset "xIndex"
return days[xIndex];
}
console.log('returns Fri:', getWeekDayFromOffset('Wed', 2));
console.log('returns Thu:', getWeekDayFromOffset('Sat', 5));Robert Thorne covers electric vehicle innovations, autonomous driving systems, global mobility trends, and automotive engineering developments.
