Leetcode 249. Group Shifted Strings
I Am Solving the Leetcode Question 249. Group Shifted Strings. Can Someone Please Explain How the Keys Are Stored in the hashMap? We Can Shift a String by...
I am solving the leetcode question 249. Group Shifted Strings. Can someone please explain how the keys are stored in the hashMap?
We can shift a string by shifting each of its letters to its successive letter.
For example, "abc" can be shifted to be "bcd". We can keep shifting the string to form a sequence. For example, we can keep shifting "abc" to form the sequence: "abc" -> "bcd" -> ... -> "xyz".
Given an array of strings strings, group all strings[i] that belong to the same shifting sequence. You may return the answer in any order.
Input: strings = ["abc","bcd","acef","xyz","az","ba","a","z"]
Output: [["acef"],["a","z"],["abc","bcd","xyz"],["az","ba"]]
func groupStrings(_ strings: [String]) -> [[String]] {
var dict = [[Int]: [String]]()
for word in strings {
var key = [0]
if word.count > 1 {
var a = Array(word)
let pivot = Int(a[0].asciiValue!) - 97
for i in 1..<a.count {
let index = (Int(a[i].asciiValue!) - 97 + 26 - pivot) % 26
key.append(index)
}
}
if var array = dict[key] {
array.append(word)
dict[key] = array
} else {
dict[key] = [word]
}
}
return dict.keys.compactMap { dict[$0] }
}
"[[0, 2, 4, 5]: ["acef"], [0, 25]: ["az", "ba"], [0]: ["a", "z"], [0, 1, 2]: ["abc", "bcd", "xyz"]]"
1 Answer
Your question is not much clear but I believe u are requesting an explanation to the groupStrings function.
In your question u have to find the shifting sequences. eg : abc -> bcd -> cde ..... -> xyz.
So the logic behind this is checking the ASCII values of each character. Because if two strings form a shifting sequence the differences between the ASCII values of any consecutive pair of their characters are the same.
For an example we know abc bcd xyz are in a shifting sequence`.
Characters ASCCI values Difference from the 1st value
a b c 97 98 99. 0 1 2
b c d 98 99 100. 0 1 2
x y z 120 121 122. 0 1 2
Basically what happening in your function is creating a dictionary which contains those differences as keys and strings as values.
func groupStrings(_ strings: [String]) -> [[String]] {
var dict = [[Int]: [String]]() // initialize the dictionary
for word in strings {
var key = [0]
if word.count > 1 {
var a = Array(word) //create an array from the charachters of the word
let pivot = Int(a[0].asciiValue!) - 97 // get the ASCII value of the 1st lestter
// we substract 97 because for english letters ASCII values start from 97.
// by substracting 97 we can map the ASCCII of a to 0, b to 1 .... z to 26
for i in 1..<a.count {
// calulate the differences between the ASCII values of any consecutive pairs
let index = (Int(a[i].asciiValue!) - 97 + 26 - pivot) % 26
key.append(index)
}
}
// here check if there is an already a difference sequence in the dictionary
//if true we append the word to that exsiting key value pair
//else create a new key value pair
if var array = dict[key] {
array.append(word)
dict[key] = array
} else {
dict[key] = [word]
}
}
return dict.keys.compactMap { dict[$0] }
}
Alexander Ross has covered the video game industry for a decade, writing deep dives on game design, esports tournaments, VR developments, and gaming culture.
