Len() of a Numpy Array in Python [Duplicate]
If I Use Len(Np. Array([[2,3,1,0], [2,3,1,0], [3,2,1,1]])), I Get Back 3. Why Is There No Argument for Len() About Which Axis I Want the Length of in...
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If I use len(np.array([[2,3,1,0], [2,3,1,0], [3,2,1,1]])), I get back 3.
Why is there no argument for len() about which axis I want the length of in multidimensional arrays? This is alarming. Is there an alternative?
What is the len of the equivalent nested list?
len([[2,3,1,0], [2,3,1,0], [3,2,1,1]])
With the more general concept of shape, numpy developers choose to implement __len__ as the first dimension. Python maps len(obj) onto obj.__len__.
X.shape returns a tuple, which does have a len - which is the number of dimensions, X.ndim. X.shape[i] selects the ith dimension (a straight forward application of tuple indexing).
Easy. Use .shape.
>>> nparray.shape
(5, 6) #Returns a tuple of array dimensions.
You can transpose the array if you want to get the length of the other dimension.
len(np.array([[2,3,1,0], [2,3,1,0], [3,2,1,1]]).T)
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