Local (?) Variable Referenced Before Assignment [Duplicate]

Question

test1 = 0
def testFunc():
    test1 += 1
testFunc()

I am receiving the following error:

UnboundLocalError: local variable 'test1' referenced before assignment.

Error says that 'test1' is local variable but i thought that this variable is global

So is it global or local and how to solve this error without passing global test1 as argument to testFunc?

Accepted Answer

In order for you to modify test1 while inside a function you will need to do define test1 as a global variable, for example:

test1 = 0
def testFunc():
    global test1 
    test1 += 1
testFunc()

However, if you only need to read the global variable you can print it without using the keyword global, like so:

test1 = 0
def testFunc():
     print test1 
testFunc()

But whenever you need to modify a global variable you must use the keyword global.

Answer 2

Best solution: Don't use globals

>>> test1 = 0
>>> def test_func(x):
        return x + 1

>>> test1 = test_func(test1)
>>> test1
1

Answer 3

You have to specify that test1 is global:

test1 = 0
def testFunc():
    global test1
    test1 += 1
testFunc()

3 Answers