Passing a Multidimensional Array to a Function in Python
I Was Just Trying an Maze-Mouse Game, to Retain the Position of the Mouse in Array, I Created a Multidimensional Array in Python Maze = [[0 for X in Range(8)]...
I was just trying an maze-mouse game, to retain the position of the mouse in array,
I created a multidimensional array in python
maze = [[0 for x in range(8)] for x in range(8)]
and I called a function using
l = move_mouse(m,maze)
function is
def move_mouse(m,maze =[i][j]):
if m=='down':
i = i+1
return maze
How to pass the array with with values i and j in maze so that to retain the current position and return the same to main function?
Please tell if I'm wrong in assigning it.
1 Answer
The maze and the position are two different objects, you cannot mix them in a way you tried. Keep them separate:
def move_mouse(m, maze, pos):
if m == 'down':
# check the maze
pos = pos[0], pos[1] + 1
return pos
maze = [[0 for x in range(8)] for x in range(8)]
pos = (4,4)
pos = move_mouse('down', maze, pos)
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