Program Gets 101 Numbers Instead of 100 [Closed]

Question

This is a simple C program which gets 100 numbers from user and counts even and odd numbers. Problem is that it gets 101 numbers instead of 100. i checked it twice and i can't figure it out.

#include <stdio.h>

int main() {

    unsigned int i;
    int numbers[101];
    int even = 0, odd = 0;


    printf("%s", "Enter 100 numbers:\n");

    for (i = 0; i < 101; i++) {

        scanf("%d", &numbers[i]);

        if (numbers[i] % 2 == 0)
            even++;
        else
            odd++;

        printf("even is %d odd is %d\n", even, odd);
    }

    return 0;
}

Accepted Answer

Just change this:

int numbers[101];

to:

int numbers[100];

and this:

for (i=0; i<101; i++)

to:

for (i=0; i<100; i++)

Also so you wouldn't have to change this number in 2 places you could define a constant like this:

#define SIZE 100

and then you can use the constant instead(int numbers[SIZE];, for (i=0; i<SIZE; i++))!

Accepted Answer

If you start counting from zero, you will count an extra number.

0 ... 1 => this is 2 numbers

0... 100 => this is 101 numbers

So count from 1 to 100, or from 0 to 99 - e.g.

for (i=0; i<100; i++)

Program Gets 101 Numbers Instead of 100 [Closed]

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2 Answers

Chloe Bennett