Python Array Group Count
In Python, I Have an Array Of, ("192.168.1.1","High"), ("192.168.1.1","High"), ("192.168.1.1","Low"), ("192.168.1.1","Low"), ("192.168.1.2","High")...
In Python, I have an array of,
("192.168.1.1","high"),("192.168.1.1","high"),("192.168.1.1","low"),("192.168.1.1","low"),("192.168.1.2","high"),("192.168.1.2","medium")
and I need an output by showing count
("192.168.1.1","high",2),("192.168.1.1","low",2),("192.168.1.2","high",1),("192.168.1.2","medium",1)
anyone please help me
2 Answers
You can use Counter from collections.
from collections import Counter
l = [("192.168.1.1","high"),("192.168.1.1","high"),("192.168.1.1","low"),("192.168.1.1","low"),("192.168.1.2","high"),("192.168.1.2","medium")]
counter = Counter(l)
result = [(*key, counter[key]) for key in counter]
If you don't care about order:
l = [("192.168.1.1","high"),("192.168.1.1","high"),("192.168.1.1","low"),("192.168.1.1","low"),("192.168.1.2","high"),("192.168.1.2","medium")]
list(set([(*t, l.count(t)) for t in l]))
James Sterling reports on renewable energy developments, climate policy, ecological conservation, and green tech innovations around the globe.
