Python Error - Typeerror: Input Expected at Most 1 Arguments, Got 3 [Duplicate]

Question

Can someone explain why I can not use your_name in the goal variable?

my_name = "Bryson"
my_age = 29
your_name = input ("What is your name? ")
your_age = input ("What is your age? ")
print ("My name is", my_name,", and I am", my_age, "years old.")
print ("Your name is", your_name,", and you are", your_age,".")
print("Thank you for buying my book,", your_name,"!")
goal = input ("What was your favorite part of the book,", your_name, "?")
print("Awesome!")

The error I get is:

goal = input ("What was your favorite part of the book,", your_name, "?")
TypeError: input expected at most 1 arguments, got 3

Accepted Answer

You got that error because you in fact gave 3 arguments to the input function when it was only expecting 1 (namely, a string prompt).

In input ("What was your favorite part of the book,", your_name, "?")
           ---------------------------------------- , ---------, ---

The underlined parts are the comma-separated arguments: a string ("What is ....book", a variable your_name, and another string, "?"

I think what you wanted was

goal = input("What was your favorite part of the book, " + your_name + "?")

Here the concatenation operator + combines those ingredients into a single string -- and a string is the one argument that input is expecting

Answer 2

Try this:

goal = input ("What was your favorite part of the book, %s ?" % your_name)

Answer 3

input(print("What was your favorite part of the book, " + your_name + "?"))

Python Error - Typeerror: Input Expected at Most 1 Arguments, Got 3 [Duplicate]

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3 Answers

Chloe Bennett