Python Giving Filenotfounderror for File Name Returned by Os. Listdir
I Was Trying to Iterate over the Files in a Directory Like This: Import Os Path = R'e: /Somedir' for Filename in Os. Listdir(Path): F = Open(Filename, 'R')...
I was trying to iterate over the files in a directory like this:
import os
path = r'E:/somedir'
for filename in os.listdir(path):
f = open(filename, 'r')
... # process the file
But Python was throwing FileNotFoundError even though the file exists:
Traceback (most recent call last):
File "E:/ADMTM/TestT.py", line 6, in <module>
f = open(filename, 'r')
FileNotFoundError: [Errno 2] No such file or directory: 'foo.txt'
So what is wrong here?
2 Answers
It is because os.listdir does not return the full path to the file, only the filename part; that is 'foo.txt', when open would want 'E:/somedir/foo.txt' because the file does not exist in the current directory.
Use os.path.join to prepend the directory to your filename:
path = r'E:/somedir'
for filename in os.listdir(path):
with open(os.path.join(path, filename)) as f:
... # process the file
(Also, you are not closing the file; the with block will take care of it automatically).
os.listdir(directory) returns a list of file names in directory. So unless directory is your current working directory, you need to join those file names with the actual directory to get a proper absolute path:
for filename in os.listdir(path):
filepath = os.path.join(path, filename)
f = open(filepath,'r')
raw = f.read()
# ...
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