Reeborg's World Around 1 - Variable (Python's While Loop)

def turn_right():
    turn_left()
    turn_left()
    turn_left()
def jump():
    move()
    turn_left()
    move()
    turn_right()
    move()
    turn_right()
    move()
    turn_left()
        
def turn_up():
    turn_left()
    move()
    turn_right()
    move()
    turn_right()
    move()
    turn_left()
        

#for steps in range (0, 5):
    #jump()
#hurdle = 6
while at_goal() != True:
    
    if wall_in_front() == True:
        turn_up()
    elif front_is_clear() == True:
        move()
    

    
This is how I solved mine for puzzle 3

This is how I finished the same exercise:

put()

while not wall_in_front():
    move()
    if wall_in_front():
        turn_left()
    elif object_here():
        done()

Basically:

• It moves straight while there is not wall in the front and it keeps checks with a while loop if there is wall or not in front.
• If there is a wall it turns left and gets in while loop again.
• To stop the while loop; to determine the starting point first I left a token with put() function. With an elif statement after if statement I have used object_here() function so it can detect the object and stop the while loop with done() function.

If anyone has an better solution for that I'd love to see different approaches.

I fiddled a little more on this problem and found a way to solve it

def walk():
    while wall_on_right() and not wall_in_front():
        if object_here():
            take()
            done()
        else:
            move()
def turn():
    while wall_on_right() and wall_in_front():
        turn_left()
        move()
put("token")
move()

while True:
    walk()
    turn()

The problem mostly consists of how I was understanding the object_here () function since, as mentioned in their page "Reeborg can determine whether or not there is at least one object at his location". Therefore, adding a take () and done () function in case Reeborg detected an object in a given field was able to do the trick.