Removing Whitespace from Strings in Java

I have a string like this:

mysz = "name=john age=13 year=2001";

I want to remove the whitespaces in the string. I tried trim() but this removes only whitespaces before and after the whole string. I also tried replaceAll("\\W", "") but then the = also gets removed.

How can I achieve a string with:

mysz2 = "name=johnage=13year=2001"
7

37 Answers

st.replaceAll("\\s+","") removes all whitespaces and non-visible characters (e.g., tab, \n).


st.replaceAll("\\s+","") and st.replaceAll("\\s","") produce the same result.

The second regex is 20% faster than the first one, but as the number consecutive spaces increases, the first one performs better than the second one.


Assign the value to a variable, if not used directly:

st = st.replaceAll("\\s+","")
6
replaceAll("\\s","")

\w = Anything that is a word character

\W = Anything that isn't a word character (including punctuation etc)

\s = Anything that is a space character (including space, tab characters etc)

\S = Anything that isn't a space character (including both letters and numbers, as well as punctuation etc)

(Edit: As pointed out, you need to escape the backslash if you want \s to reach the regex engine, resulting in \\s.)

0

The most correct answer to the question is:

String mysz2 = mysz.replaceAll("\\s","");

I just adapted this code from the other answers. I'm posting it because besides being exactly what the question requested, it also demonstrates that the result is returned as a new string, the original string is not modified as some of the answers sort of imply.

(Experienced Java developers might say "of course, you can't actually modify a String", but the target audience for this question may well not know this.)

3

How about replaceAll("\\s", ""). Refer here.

1

One way to handle String manipulations is StringUtils from Apache commons.

String withoutWhitespace = StringUtils.deleteWhitespace(whitespaces);

You can find it here. commons-lang includes lots more and is well supported.

0

If you need to remove unbreakable spaces too, you can upgrade your code like this :

st.replaceAll("[\\s|\\u00A0]+", "");
3

You should use

s.replaceAll("\\s+", "");

instead of:

s.replaceAll("\\s", "");

This way, it will work with more than one spaces between each string. The + sign in the above regex means "one or more \s"

--\s = Anything that is a space character (including space, tab characters etc). Why do we need s+ here?

3

If you prefer utility classes to regexes, there is a method trimAllWhitespace(String) in StringUtils in the Spring Framework.

1

You've already got the correct answer from Gursel Koca but I believe that there's a good chance that this is not what you really want to do. How about parsing the key-values instead?

import java.util.Enumeration;
import java.util.Hashtable;

class SplitIt {
  public static void main(String args[])  {

    String person = "name=john age=13 year=2001";

    for (String p : person.split("\\s")) {
      String[] keyValue = p.split("=");
      System.out.println(keyValue[0] + " = " + keyValue[1]);
    }
  }
}

output:
name = john
age = 13
year = 2001

The easiest way to do this is by using the org.apache.commons.lang3.StringUtils class of commons-lang3 library such as "commons-lang3-3.1.jar" for example.

Use the static method "StringUtils.deleteWhitespace(String str)" on your input string & it will return you a string after removing all the white spaces from it. I tried your example string "name=john age=13 year=2001" & it returned me exactly the string that you wanted - "name=johnage=13year=2001". Hope this helps.

You can do it so simply by

String newMysz = mysz.replace(" ","");
2
public static void main(String[] args) {        
    String s = "name=john age=13 year=2001";
    String t = s.replaceAll(" ", "");
    System.out.println("s: " + s + ", t: " + t);
}

Output:
s: name=john age=13 year=2001, t: name=johnage=13year=2001

I am trying an aggregation answer where I test all ways of removing all whitespaces in a string. Each method is ran 1 million times and then then the average is taken. Note: Some compute will be used on summing up all the runs.


Results:

1st place from @jahir 's answer

  • StringUtils with short text: 1.21E-4 ms (121.0 ms)
  • StringUtils with long text: 0.001648 ms (1648.0 ms)

2nd place

  • String builder with short text: 2.48E-4 ms (248.0 ms)
  • String builder with long text: 0.00566 ms (5660.0 ms)

3rd place

  • Regex with short text: 8.36E-4 ms (836.0 ms)
  • Regex with long text: 0.008877 ms (8877.0 ms)

4th place

  • For loop with short text: 0.001666 ms (1666.0 ms)
  • For loop with long text: 0.086437 ms (86437.0 ms)

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Sarah Jenkins

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