Rounding Float Number to the Nearest Tenth

Hi i have a number like 1.3333333333(THE RESULT OF PYTHON DIVISION) to round of to the nearest tenth

Input

1.333333333

Output

1.34 or 1.3

Here is what i tried

    def round(self,oj):
        try:
            (bd,ad) = oj.split(".")
            if int(ad[1]) >5:
                up = True   
            else:
                up= False
            if up:
                if ad[0]==9:
                    oj = str(int(bd)+1)
                
                else:
                    oj = str(bd)+"."+str(int(ad[0])+1)
            else:
                oj =str( bd)+"."+ad[0]
        except IndexError:
            pass
        
        return float(oj)    
        

But i believe there is a better way to do it so please tell any suggestions you have