Ruby Using Each_Slice. To_A
I'm Trying to Subdivide an Array into Pairs of Arrays. for Example: ["A","B","C","D"] Should Become [["A","B"], ["C","D"]. I Believe I've Succeeded by Doing...
I'm trying to subdivide an array into pairs of arrays.
For example: ["A","B","C","D"] should become [["A","B"],["C","D"].
I believe I've succeeded by doing arg.each_slice(2).to_a.
But if I were then to do arg.length on the new array I still get 4.
I expect to get 2 (in the above example).
In the end, I want to be able to call the first element of arg to be ["A","B"] but at the moment, I am still getting "A".
3 Answers
array = ["A", "B", "C", "D"]
array
=> ["A", "B", "C", "D"]
array.each_slice(2).to_a
=> [["A", "B"], ["C", "D"]]
array.each_slice(2).to_a.length
=> 2
Maybe you are expecting that array.each_slice(2).to_a will change your original array, but here you will have new Array object, because each_slice is non-destructive method, like most in ruby.
new_array = array.each_slice(2).to_a
new_array
=> [["A", "B"], ["C", "D"]]
new_array[0]
=> ["A", "B"]
try
arg = arg.each_slice(2).to_a
In ruby methods that change state of there instances usually has !at the end. For example
hash1.merge!(hash2)
Try this
1.9.2p180 :015 > ['A', 'B', 'C', 'D'].each_slice(2).to_a[0]
=> ["A", "B"]
works fine
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