Size of Numpy Array
Is There an Equivalent to the Matlab Size() Command in Numpy? in Matlab, >>> a = Zeros(2,5) 0 0 0 0 0 0 0 0 0 0 >>> Size(A) 2 5 in Python, >>> a = Zeros((2,5))...
Is there an equivalent to the MATLAB
size()
command in Numpy?
In MATLAB,
>>> a = zeros(2,5)
0 0 0 0 0
0 0 0 0 0
>>> size(a)
2 5
In Python,
>>> a = zeros((2,5))
>>>
array([[ 0., 0., 0., 0., 0.],
[ 0., 0., 0., 0., 0.]])
>>> ?????
3 Answers
This is called the "shape" in NumPy, and can be requested via the .shape attribute:
>>> a = zeros((2, 5))
>>> a.shape
(2, 5)
If you prefer a function, you could also use numpy.shape(a).
Yes numpy has a size function, and shape and size are not quite the same.
Input
import numpy as np
data = [[1, 2, 3, 4], [5, 6, 7, 8]]
arrData = np.array(data)
print(data)
print(arrData.size)
print(arrData.shape)
Output
[[1, 2, 3, 4], [5, 6, 7, 8]]
8 # size
(2, 4) # shape
[w,k] = a.shape will give you access to individual sizes if you want to use it for loops like in matlab
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