Title for Matplotlib Legend
I Know It Seems Fairly Redundant to Have a Title for a Legend, but Is It Possible Using Matplotlib? Here's a Snippet of the Code I Have: Import Matplotlib...
I know it seems fairly redundant to have a title for a legend, but is it possible using matplotlib?
Here's a snippet of the code I have:
import matplotlib.patches as mpatches
import matplotlib.pyplot as plt
one = mpatches.Patch(facecolor='#f3f300', label='label1', linewidth = 0.5, edgecolor = 'black')
two = mpatches.Patch(facecolor='#ff9700', label = 'label2', linewidth = 0.5, edgecolor = 'black')
three = mpatches.Patch(facecolor='#ff0000', label = 'label3', linewidth = 0.5, edgecolor = 'black')
legend = plt.legend(handles=[one, two, three], loc = 4, fontsize = 'small', fancybox = True)
frame = legend.get_frame() #sets up for color, edge, and transparency
frame.set_facecolor('#b4aeae') #color of legend
frame.set_edgecolor('black') #edge color of legend
frame.set_alpha(1) #deals with transparency
plt.show()
I would want the title of the legend above label1. For reference, this is the output:
3 Answers
Add the title parameter to the this line:
legend = plt.legend(handles=[one, two, three], title="title",
loc=4, fontsize='small', fancybox=True)
See also the official docs for the legend constructor.
Just to add to the accepted answer that this also works with an Axes object.
fig, ax = plt.subplots()
ax.plot([0, 1, 2], [0, 1, 4], label='some_label') # Or however the Axes was created.
ax.legend(title='This is My Legend Title')
In case you have an already created legend, you can modify its title with set_title(). For the first answer:
legend = plt.legend(handles=[one, two, three], loc=4, fontsize='small', fancybox=True)
legend.set_title("title")
# plt.gca().get_legend().set_title() if you didn't store the
# legend in an object or you're loading a saved figure.
For the second answer based on Axes:
fig, ax = plt.subplots()
ax.plot([0, 1, 2], [0, 1, 4], label='some_label') # Or however the Axes was created.
ax.legend()
ax.get_legend().set_title("title")
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