Using Regex to Match Any Character Except =
I Am Trying to Write a String Validation to Match Any Character (Regular, Digit and Special) Except =. Here Is What I Have Written - String patternString =...
I am trying to write a String validation to match any character (regular, digit and special) except =.
Here is what I have written -
String patternString = "[[^=][\\w\\s\\W]]*";
Pattern p = Pattern.compile(patternString);
Matcher m = p.matcher(str);
if(m.matches())
System.out.println("matches");
else
System.out.println("does not");
But, it matches the input string "2009-09/09 12:23:12.5=" with the pattern.
How can I exclude = (or any other character, for that matter) from the pattern string?
4 Answers
If the only prohibited character is the equals sign, something like [^=]* should work.
[^...] is a negated character class; it matches a single character which is any character except one from the list between the square brackets. * repeats the expression zero or more times.
First of all, you don't need a regexp. Simply call contains:
if(str.contains("="))
System.out.println("does not");
else
System.out.println("matches");
The correct regexp you're looking for is just
String patternString = "[^=]*";
If your goal is to not have any = characters in your string, please try the following
String patternString = "[^=]*";
If you only want to check for occurence of "=" why don't you use the String indexOf() method?
if str.indexOf('=') //...
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