Varied Amounts of Input Data
Problem: Statistics Are Often Calculated with Varying Amounts of Input Data. Write a Program That Takes Any Number of Non-Negative Integers as Input, and...
Problem: Statistics are often calculated with varying amounts of input data. Write a program that takes any number of non-negative integers as input, and outputs the average and max. A negative integer ends the input and is not included in the statistics.
Ex: When the input is: 15 20 0 5 -1
the output is: 10 20
You can assume that at least one non-negative integer is input.
import java.util.Scanner;
public class LabProgram {
public static void main(String[] args) {
Scanner scnr = new Scanner (System.in);
int num = 0;
int count = 0;
int max = 0;
int total = 0;
int avg = 0;
do {
total += num;
num = scnr.nextInt();
count = ++count;
if (num >= max) {
max = num;
}
} while (num >= 0);
avg = total/(count-1);
System.out.println(avg + " " + max);
}
}
I had a lot of trouble with this problem. Is there any way I could have done this without having to do count -1 while computing the average? Also, is this this the most efficient way I could have done it?
3 Answers
How about this? If you have questions from the implementation, please ask.
public static void main(String[] args) throws IOException {
Scanner scnr = new Scanner(System.in);
int count = 0, max = 0, total = 0;
int num = scnr.nextInt();
while (num >= 0) {
count++;
total += num;
max = Math.max(max, num);
num = scnr.nextInt();
}
int avg = count == 0 ? 0 : total/count;
System.out.println(avg + " " + max);
}
If you use while loop instead of do-while loop, you don't have to count the negative number input anymore. And no, it's not the most efficient way, but it's a good start!
import java.util.Scanner;
public class LabProgram {
public static void main(String[] args) {
Scanner scnr = new Scanner (System.in);
int userNum;
int maxNum = 0;
int totalSum = 0;
int averageNum;
int count = 0;
userNum = scnr.nextInt();
while (userNum >= 0) {
if (userNum > maxNum) {
maxNum = userNum;
}
totalSum += userNum;
++count;
userNum = scnr.nextInt();
}
averageNum = totalSum / count;
System.out.println("" + averageNum + " " + maxNum);
}
}
int Num;
int max = 0;
int total = 0;
int average;
int count = 0;
Num = scnr.nextInt();
while (Num >= 0) {
if (Num > max) {
max = Num;
}
total += Num;
++count;
Num = scnr.nextInt();
}
average = total / count;
System.out.println("" + average + " " + max);
}
}
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