What Does Mockito. anyLong() Do?

Question

I have to test a method which takes a Long as argument. I have to test it for any value of the Long and also in case it's null. Does Mockito.anyLong() automatically test both cases? null and any value of the Long? Or randomly picks up a value between any long value and null? Considering that these are the docs about anyLong():

anyLong

public static long anyLong()

any long, Long or null.

See examples in javadoc for Matchers class

Returns:
    0.

Thanks in advance.

Accepted Answer

It's a matcher, not a test value generator. It's used for saying things like "I expect this stubbed method to be called with any long, Long or null but I don't care about the exact value".

Answer 2

If you have long parameter and you manage to pass null as an argument to mock there will be NPE. If you have Long parameter anyLong() will allow Long and null, long will be autoboxed to Long by compiler. Try this

public class X  {
    long x(Long arg) {
        return 0;
    }

    public static void main(String[] args) {
        X x = mock(X.class);
        when(x.x(anyLong())).thenReturn(0L);
        System.out.println(x.x(null));
    }
}

it will print

0
0

What Does Mockito. anyLong() Do?

2 Answers

Must Read

Your Answer

Robert Thorne

What Does Mockito. anyLong() Do?

2 Answers

Must Read

Your Answer

Sign up or log in

Post as a guest

Robert Thorne